@Anonymous said:
i think it’s true; you can express 1/1-x as an infinite geometric sum (like gaussian)
The taylor series for this function convergences only when |x|<1. I wonder if that is an issue.
yes, that is important. i think that’s why the vector norms were bounded strictly by 1, and hence the dot product is also strictly bounded by 1 by Cauchy-Schwarz, so the taylor series converges
Today's kernel function question
Was the kernel given in the today's true or false question valid or not?
i think it’s true; you can express 1/1-x as an infinite geometric sum (like gaussian)
4
The taylor series for this function convergences only when |x|<1. I wonder if that is an issue.
1
but wasn't |x|<1 stated as an additional condition in the question?
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yes, that is important. i think that’s why the vector norms were bounded strictly by 1, and hence the dot product is also strictly bounded by 1 by Cauchy-Schwarz, so the taylor series converges
4
I don't know about the convergence of infinite series but I decided to believe in this kernel
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