Exam 2020: Q2

Why isn't sin(x) with x between pi and 2pi strongly convex?

Top comment

The second derivative is arbitrary close to zero since $$x$$ is arbitrary close to $$\pi$$ and $$2\pi$$. Thus we only have strict convexity here.

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Hi,
The previous answer is correct, intuitively it is because sin(x) "behaves like linear" around $$\pi$$ and $$2 \pi$$.
Best.
Scott

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