Hi, I understand that as sigma tends to 0 qkn converges towards zkn. But I don't understand why that means the algorithm is equivalent to k means? reference: lecture 11b EM, around 53:00 in the video lecture.

thank you

## lecture 11 EM kmeans

Hi,

I understand that as sigma tends to 0 qkn converges towards zkn. But I don't understand why that means the algorithm is equivalent to k means? reference: lecture 11b EM, around 53:00 in the video lecture.

thank you

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